0.01x^2-0.02x-0.01=0

Solution for 0.01x^2-0.02x-0.01=0 equation:

0.01x^2-0.02x-0.01=0

a = 0.01; b = -0.02; c = -0.01;
Δ = b2-4ac
Δ = -0.022-4·0.01·(-0.01)
Δ = 0.0008
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.02)-\sqrt{0.0008}}{2*0.01}=\frac{0.02-\sqrt{0.0008}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.02)+\sqrt{0.0008}}{2*0.01}=\frac{0.02+\sqrt{0.0008}}{0.02}
$